NCERT Solutions for Class 10 Maths Chapter 2 Polynomials

NCERT Solutions for Class 10 Maths Chapter 2 Polynomials

Upcoming Event

CBSE Class 10th Exam Date:15 Jul' 2025 - 15 Jul' 2025

Apoorva SinghUpdated on 25 Jun 2025, 09:51 PM IST

Have you ever noticed how the path of a roller coaster, the trajectory of a football, or the economic trend predictions follow a certain pattern, that is the power of polynomials. Polynomials are not just some algebraic expression; they are one of the main pillars of mathematics. As per the latest syllabus, this chapter contains the basic concepts of polynomials like Degree of Polynomials, Zeroes of a Polynomial, Geometrical Meaning of the Zeroes of a Polynomial, and Relationship between Zeroes and Coefficients of a Polynomial. Understanding these concepts will make students more efficient in solving problems involving polynomials and will also build a strong foundation for advanced polynomial concepts. NCERT Solutions for Class 10 can help the students immensely in this regard.

This NCERT Solutions for class 10 Maths article about Polynomials is designed by our experienced subject experts to offer a systematic and structured approach to these important concepts and help students to prepare well for exams and to gain knowledge about all the natural processes happening around them by a series of solved questions given in the NCERT textbook exercise. It covers questions from all the topics and will help you improve your speed and accuracy. The solutions for other subjects and classes can be downloaded from the NCERT Solutions.

NCERT Solutions for Class 10 Maths Chapter 2 Polynomials PDF Free Download

Students who wish to access the NCERT solutions for class 10, chapter 2 can click on the link below to download the entire solution in PDF.

Download Solution PDF

NCERT Solutions for Class 10 Maths Chapter 2: Exercise Questions

Polynomials Class 10 Exercise: 2.1
Total Questions: 1
Page number: 18
Aakash Repeater Courses

Take Aakash iACST and get instant scholarship on coaching programs.

Q1 (1): The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the numbers of zeroes of p(x), in each case.

1635918537229

Answer: The number of zeroes of p(x) is zero as the curve does not intersect the x-axis.

Q1 (2): The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

1635918562539

Answer: The number of zeroes of p(x) is one as the curve intersects the x-axis only once.

Q1 (3): The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

1635918572380

Answer: The number of zeroes of p(x) is three as the graph intersects the x-axis thrice.

Q1 (4): The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

1635918582058

Answer: The number of zeroes of p(x) is two as the graph intersects the x-axis twice.

Q1 (5): The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

1635918596067

Answer: The number of zeroes of p(x) is four as the graph intersects the x-axis four times.

Q1 (6): The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

1635918606641

Answer: The number of zeroes of p(x) is three as the graph intersects the x-axis thrice.

Polynomials Class 10 Exercise: 2.2
Total Questions: 2
Page number: 23

Q1 (i): Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $x^2-2 x-8$

Answer:

x 2 - 2x - 8 = 0

x 2 - 4x + 2x - 8 = 0

x(x-4) +2(x-4) = 0

(x+2)(x-4) = 0

The zeroes of the given quadratic polynomial are -2 and 4

$\\\alpha =-2\\, \beta =4$

VERIFICATION

Sum of roots:

$
\begin{aligned}
& \alpha+\beta=-2+4=2 \\
& -\frac{\text { coefficient of } x}{\text { coefficient of } x^2} \\
& =-\frac{-2}{1} \\
& =2 \\
& =\alpha+\beta
\end{aligned}
$


Verified
Product of roots:

$
\begin{aligned}
& \alpha \beta=-2 \times 4=-8 \\
& \frac{\text { constant term }}{\text { coefficient of } x^2} \\
& =\frac{-8}{1} \\
& =-8 \\
& =\alpha \beta
\end{aligned}
$

Verified

Q1 (ii): Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $4 s^2-4 s+1$

Answer:

$
\begin{aligned}
& 4 s^2-4 s+1=0 \\
& 4 s^2-2 s-2 s+1=0 \\
& 2 s(2 s-1)-1(2 s-1)=0 \\
& (2 s-1)(2 s-1)=0
\end{aligned}
$


The zeroes of the given quadratic polynomial are $1 / 2$ and $1 / 2$

$
\begin{aligned}
& \alpha=\frac{1}{2} \\
& \beta=\frac{1}{2}
\end{aligned}
$


VERIFICATION
Sum of roots:

$
\alpha+\beta=\frac{1}{2}+\frac{1}{2}=1
$

$
\begin{aligned}
& -\frac{\text { coefficient of } x}{\text { coefficient of } x^2} \\
& =-\frac{-4}{4} \\
& =1 \\
& =\alpha+\beta
\end{aligned}
$


Verified
Product of roots:

$
\begin{aligned}
& \alpha \beta=\frac{1}{2} \times \frac{1}{2}=\frac{1}{4} \\
& \frac{\text { constant term }}{\text { coefficient of } x^2} \\
& =\frac{1}{4} \\
& =\alpha \beta
\end{aligned}
$

Verified

Q1 (iii): Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $6 x^2-3-7 x$

Answer:

6x 2 - 3 - 7x = 0

6x 2 - 7x - 3 = 0

6x 2 - 9x + 2x - 3 = 0

3x(2x - 3) + 1(2x - 3) = 0

(3x + 1)(2x - 3) = 0

The zeroes of the given quadratic polynomial are -1/3 and 3/2

$
\begin{aligned}
& \alpha=-\frac{1}{3} \\
& \beta=\frac{3}{2}
\end{aligned}
$


Sum of roots:

$
\begin{aligned}
& \alpha+\beta=-\frac{1}{3}+\frac{3}{2}=\frac{7}{6} \\
& -\frac{\text { coefficient of } x}{\text { coefficient of } x^2} \\
& =-\frac{-7}{6} \\
& =\frac{7}{6} \\
& =\alpha+\beta
\end{aligned}
$

Verified

Product of roots:

$\begin{aligned} & \alpha \beta=-\frac{1}{3} \times \frac{3}{2}=-\frac{1}{2} \\ & \frac{\text { constant term }}{\text { coefficient of } x^2} \\ & =\frac{-3}{6} \\ & =-\frac{1}{2} \\ & =\alpha \beta\end{aligned}$

Verified

Q1 (iv): Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $4 u^2+8 u$

Answer:
4u 2 + 8u = 0

4u(u + 2) = 0

The zeroes of the given quadratic polynomial are 0 and -2

$
\begin{aligned}
& \alpha=0 \\
& \beta=-2
\end{aligned}
$


VERIFICATION
Sum of roots:

$
\begin{aligned}
& \alpha+\beta=0+(-2)=-2 \\
& -\frac{\text { coefficient of } x}{\text { coefficient of } x^2} \\
& =-\frac{8}{4} \\
& =-2 \\
& =\alpha+\beta
\end{aligned}
$


Verified
Product of roots:

$
\alpha \beta=0 \times-2=0
$

$\begin{aligned} & \frac{\text { constant term }}{\text { coeff ficient of } x^2} \\ & =\frac{0}{4} \\ & =0 \\ & =\alpha \beta\end{aligned}$

Verified

Q1 (v): Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $t^2-15$

Answer:
t 2 - 15 = 0

$
(t-\sqrt{15})(t+\sqrt{15})=0
$


The zeroes of the given quadratic polynomial are $-\sqrt{15}$ and $\sqrt{15}$

$
\begin{aligned}
& \alpha=-\sqrt{15} \\
& \beta=\sqrt{15}
\end{aligned}
$


VERIFICATION
Sum of roots:

$
\begin{aligned}
& \alpha+\beta=-\sqrt{15}+\sqrt{15}=0 \\
& -\frac{\text { coefficient of } x}{\text { coefficient of } x^2} \\
& =-\frac{0}{1} \\
& =0 \\
& =\alpha+\beta
\end{aligned}
$

Verified

Product of roots:

$\begin{aligned} & \alpha \beta=-\sqrt{15} \times \sqrt{15}=-15 \\ & \frac{\text { constant term }}{\text { coefficient of } x^2} \\ & =\frac{-15}{1} \\ & =-15 \\ & =\alpha \beta\end{aligned}$

Verified

Q1 (vi): Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $3 x^2-x-4$

Answer:
3x 2 - x - 4 = 0

3x 2 + 3x - 4x - 4 = 0

3x(x + 1) - 4(x + 1) = 0

(3x - 4)(x + 1) = 0

The zeroes of the given quadratic polynomial are 4/3 and -1

$
\begin{aligned}
& \alpha=\frac{4}{3} \\
& \beta=-1
\end{aligned}
$


VERIFICATION
Sum of roots:

$
\begin{aligned}
& \alpha+\beta=\frac{4}{3}+(-1)=\frac{1}{3} \\
& -\frac{\text { coefficient of } x}{\text { coefficient of } x^2} \\
& =-\frac{-1}{3} \\
& =\frac{1}{3} \\
& =\alpha+\beta
\end{aligned}
$

Verified

Product of roots:

$\begin{aligned} & \alpha \beta=\frac{4}{3} \times-1=-\frac{4}{3} \\ & \frac{\text { constant term }}{\text { coefficient of } x^2} \\ & =\frac{-4}{3} \\ & =\alpha \beta\end{aligned}$

Verified

Q2 (i): Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. 1/4 , -1

Answer:

$
\begin{aligned}
& \alpha+\beta=\frac{1}{4} \\
& \alpha \beta=-1
\end{aligned}
$


The required quadratic polynomial is

$
\begin{aligned}
& x^2-(\alpha+\beta)x+\alpha \beta=0 \\
& x^2-\frac{1}{4} x-1=0 \\
& 4 x^2-x-4=0
\end{aligned}
$

Q2 (ii): Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. $\sqrt{2}, 1 / 3$

Answer:

$
\begin{aligned}
& \alpha+\beta=\sqrt{2} \\
& \alpha \beta=\frac{1}{3} \\
& x^2-(\alpha+\beta)x+\alpha \beta=0 \\
& x^2-\sqrt{2} x+\frac{1}{3}=0 \\
& 3 x^2-3 \sqrt{2} x+1=0
\end{aligned}
$


The required quadratic polynomial is $3 x^2-3 \sqrt{2} x+1$

Q2 (iii): Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. $0, \sqrt{5}$

Answer:

$\begin{aligned} & \alpha+\beta=0 \\ & \alpha \beta=\sqrt{5} \\ & x^2-(\alpha+\beta)x+\alpha \beta=0 \\ & x^2-0 x+\sqrt{5}=0 \\ & x^2+\sqrt{5}=0\end{aligned}$

The required quadratic polynomial is x 2 + $\sqrt{5}$ .

Q2 (iv): Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. 1,1

Answer:

$\begin{aligned} & \alpha+\beta=1 \\ & \alpha \beta=1 \\ & x^2-(\alpha+\beta)x+\alpha \beta=0 \\ & x^2-1 x+1=0 \\ & x^2-x+1=0\end{aligned}$

The required quadratic polynomial is x 2 - x + 1

Q2 (v): Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. $-\frac{1}{4}, \frac{1}{4}$

Answer:

$\begin{aligned} & \alpha+\beta=-\frac{1}{4} \\ & \alpha \beta=\frac{1}{4} \\ & x^2-(\alpha+\beta)x+\alpha \beta=0 \\ & x^2-\left(-\frac{1}{4}\right) x+\frac{1}{4}=0 \\ & 4 x^2+x+1=0\end{aligned}$

The required quadratic polynomial is 4x 2 + x + 1

Q2 (vi): Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. 4,1

Answer:

$\begin{aligned} & \alpha+\beta=4 \\ & \alpha \beta=1 \\ & x^2-(\alpha+\beta)x+\alpha \beta=0 \\ & x^2-4 x+1=0\end{aligned}$

The required quadratic polynomial is x 2 - 4x + 1.

Polynomial Class 10 Solutions - Exercise Wise

Here are the exercise-wise links for the NCERT class 10 chapter 2 Polynomial:

Polynomials Class 10 Chapter 2: Topics

The important topics covered in the NCERT Class 10 Maths, chapter 2, Polynomials are:

  • 2.1 Introduction
  • 2.2 Geometrical Meaning of the Zeros of a
  • Polynomial
  • 2.3 Relationship between Zeros and Coefficients
  • of a Polynomial

NCERT Solutions for Class 10 Maths Chapter 2 Polynomials: Important Formulae

Polynomials

A polynomial $p(x)$ is an algebraic expression that can be written in the form of

$
p(x)=a_n x^n+\ldots+a_2 x^2+a_1 x+a_0
$

Here $a_0, a_1, a_2, \ldots, a_n$ are real numbers and each power of x is a non-negative integer.

Each real number ai is called a coefficient. The number a0  that is not multiplied by a variable is called a constant. Each product  $a_i x_i$  is a term of a polynomial. The highest power of the variable that occurs in the polynomial is called the degree of the polynomial. The leading term is the term with the highest power, and its coefficient is called the leading coefficient.

Types of Polynomials

The types of polynomials based on the number of terms are

  • Monomial: A monomial is a polynomial with one term. Eg. $3x$
  • Binomial: A binomial is a polynomial with two terms. Eg. $3x+2y$
  • Trinomial: A trinomial is a polynomial with three terms. Eg. $4x^2+ 3x+2y$
  • Multinomial: A general term for polynomials with more than three terms. Eg. $7x^5+ 5x^3+3x^2+2x=1$
  • Constant Polynomial: A constant polynomial is a polynomial with no variable terms but with only a constant term. Eg. $P(x) = 5$
  • Zero Polynomial: A polynomial with coefficients as zero. Eg. $0x^2+0x, 0$

Types of polynomials (based on the degree of a polynomial)

  • Linear Polynomial: A polynomial with degree one. Eg. $3x+5y = 5$
  • Quadratic Polynomial: Polynomial with degree two. any quadratic polynomial in $x$ is of the form $ax^2 + bx + c$, where $a, b, c$ are real numbers and $a \neq 0$. Eg. $2x^2+3x+2=0$
  • Cubic Polynomial: Polynomial with degree three. The general form of a cubic polynomial is $ax^3 + bx^2 + cx + d$, where $a, b, c, d$ are real numbers and $a \neq 0 $. Eg. $5x^3+3x^2+2x=1$
  • Higher-degree polynomial: Polynomials with degree more than three. Eg. $7x^5+5x^3+3$

Zeros of a Polynomial

If a real number $k$ satisfies the given polynomial, then $k$ is the zero of that polynomial. (i.e) A real number k is the zero of the polynomial $P(x)$, if $P(k) = 0$

Example: Let $P(x) = x^2 -4$. Let $x = 2$, then $P(x) = 2^2 -4 = 4-4=0$. Therefore, $2$ is the zero of the polynomial $P(x)$.

Graphical Representation of Zeros of a Polynomial

For a polynomial p(x) of degree n, the graph of y = p(x) intersects the x-axis at most n points. Therefore, a polynomial p(x) of degree n has at most n zeroes.

The number of zeros of a polynomial can be found by the number of points of the graph of the polynomial intersecting the x-axis.

Relationship Between Zeros and Coefficients of the Polynomial

Linear Polynomial:

The zero of the linear polynomial $ax+b$ = $-\frac{b}{a}$.

Quadratic Polynomial:

For the quadratic polynomial $ax^2+bx+c=0$ with zeros $x_1$ and $x_2$,

Sum of zeros, $x_1+x_2= -\frac{b}{a}$

Product of zeros $x_1 x_2= \frac{c}{a}$

Cubic Polynomial:

For the quadratic polynomial $ax^3+bx^2+cx+d=0$ with zeros $x_1$, $x_2$ and $x_3$,

Sum of zeros, $x_1+x_2= -\frac{b}{a}$

Sum of product of two zeros, $x_1 x_2+x_2 x_3+x_3 x_1= \frac{c}{a}$

Product of zeros $x_1 x_2= -\frac{d}{a}$

NCERT Solutions for Class 10 Maths: Chapter Wise

We at Careers360 compiled all the NCERT class 10 Maths solutions in one place for easy student reference. The following links will allow you to access them.

NCERT Solutions of Class 10 - Subject Wise

Students can use the following links to check the solution of maths and science-related questions in-depth.

NCERT Exemplar solutions - Subject-wise

After completing the NCERT textbooks, students should practice exemplar exercises for a better understanding of the chapters and clarity. The following links will help students to find exemplar exercises.

NCERT Books and NCERT Syllabus here

Here are some useful links for NCERT books and the NCERT syllabus for class 10:

FAQ icon
Frequently Asked Questions (FAQs)
Q: What are the polynomials in class 10 NCERT?
A:

A polynomial p(x) is an algebraic expression that can be written in the form of

$p(x)=a_nx^n+…+a_2x^2+a_1x+a_0$

Here $a_0,a_1,a_2,…,a_n$ are real numbers and each power of x is a non-negative integer.

Q: How to find the relationship between zeros and coefficients of a quadratic polynomial?
A:

Relationship between zeros and coefficients of a quadratic polynomial

For the quadratic polynomial $ax^2+bx+c=0$ with zeros $x_1$ and $x_2$,

Sum of zeros, $x_1+x_2=−b/a$

Product of zeros $x_1x_2=c/a$

Q: What is the difference between linear, quadratic and cubic polynomial?
A:

The difference between linear, quadratic and cubic polynomials is the degree of the polynomial. The degree of the linear polynomial is one, the degree of the quadratic polynomial is two, and the degree of the cubic polynomial is three.

Q: How many types of polynomials are there?
A:

Based on the number of terms, polynomials are of 4 types, monomial, binomial, trinomial and multinomial. 

Based on the degree, polynomials are of 4 types, namely, linear, quadratic, cubic and higher-degree polynomials.

Q: How to find the number of zeroes of a polynomial graphically?
A:

For a polynomial p(x) of degree n, the graph of y = p(x) intersects the x-axis at most n points. Therefore, a polynomial p(x) of degree n has at most n zeroes.

The number of zeros of a polynomial can be found by the number of points of the graph of the polynomial intersecting with the x-axis. 

Q: What is the degree of a polynomial?
A:

The highest power of the variable that occurs in the polynomial is called the degree of a polynomial.

Articles
No news available
Certifications By Top Providers
Explore Top Universities Across Globe
University of Essex, Colchester
Wivenhoe Park Colchester CO4 3SQ
University College London, London
Gower Street, London, WC1E 6BT
The University of Edinburgh, Edinburgh
Old College, South Bridge, Edinburgh, Post Code EH8 9YL
University of Nottingham, Nottingham
University Park, Nottingham NG7 2RD
Bristol Baptist College, Bristol
The Promenade, Clifton Down, Bristol BS8 3NJ
Next

Questions related to CBSE Class 10th

On Question asked by student community

Have a question related to CBSE Class 10th ?

Hello

Since you are a domicile of Karnataka and have studied under the Karnataka State Board for 11th and 12th , you are eligible for Karnataka State Quota for admission to various colleges in the state.

1. KCET (Karnataka Common Entrance Test): You must appear for the KCET exam, which is required for admission to undergraduate professional courses like engineering, medical, and other streams. Your exam score and rank will determine your eligibility for counseling.

2. Minority Income under 5 Lakh : If you are from a minority community and your family's income is below 5 lakh, you may be eligible for fee concessions or other benefits depending on the specific institution. Some colleges offer reservations or other advantages for students in this category.

3. Counseling and Seat Allocation:

After the KCET exam, you will need to participate in online counseling.

You need to select your preferred colleges and courses.

Seat allocation will be based on your rank , the availability of seats in your chosen colleges and your preferences.

4. Required Documents :

Domicile Certificate (proof that you are a resident of Karnataka).

Income Certificate (for minority category benefits).

Marksheets (11th and 12th from the Karnataka State Board).

KCET Admit Card and Scorecard.

This process will allow you to secure a seat based on your KCET performance and your category .

check link for more details

https://medicine.careers360.com/neet-college-predictor

Hope this helps you .

Hello Aspirant,  Hope your doing great,  your question was incomplete and regarding  what exam your asking.

Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.

hello Zaid,

Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.

best of luck!

According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.

You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.