NCERT Solutions for Class 7 - Download Subject wise Solution PDF

NCERT
NCERT Solutions for Class 7 - Download Subject wise Solution PDF

NCERT Solutions for Class 7 - Download Subject wise Solution PDF

Irshad AnwarUpdated on 10 Jun 2025, 04:27 PM IST

Students are greatly helped by having well-defined and complete solutions to all the questions in their textbooks. This helps a better understand of the syllabus and better prepares for exams. Discussing key topics like Maths, Science, Social Studies, Hindi, and English, these solutions not only help with homework but also help students to develop a solid academic foundation. With detailed descriptions, students find it easier to understand complicated ideas and become more interested in what they're studying. The NCERT Solutions for Class 7 can be downloaded freely in PDF format so that students can study from anywhere and at any time, as per their convenience.

These step-by-step explanations make learning easy by dividing tough problems into simple components, thus providing a stress-free and pleasant learning experience. Practising with NCERT Solutions regularly increases students' confidence levels, improves their ability to solve questions in the exam, and ultimately results in improved performance and success. It also lays a strong foundation for further classes as well as for competitive exams.

Class 7th NCERT Solutions – Marks Weightage

All subjects in Class 7 are set out of a total of 100 marks. These marks are divided into two main parts:

Internal Assessment (20 marks):
This includes marks from regular tests, projects, and classroom activities conducted throughout the year.
Summative Assessment (80 marks):
This is the final exam held at the end of the academic year, as required by the CBSE board.

The internal assessment helps track students' progress during the year, while the summative assessment estimates their understanding at the end.

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NCERT Solutions for Class 7 - Subject-wise breakdown

These are prepared on the basis of NCERT textbook exercise patterns so that students can readily understand and solve textbook exercises. Solutions of each question are explained step-wise so that students can readily understand concepts and learn to answer in the exam. Solutions are prepared as per the updated syllabus and designed as per the CBSE pattern, so students stay in sync with their curriculum.

The NCERT Solutions also include interactive features like characters like Bhoojo and Paheli, which make learning more engaging and relatable. Step-by-step solutions for every subject and chapter allow students to understand concepts while preparing for exams. Additionally, these solutions can be downloaded at no cost, making them easily available to all.

NCERT Solutions for Class 7 Maths

The Maths textbook of the 7th standard (Ganita Prakash) is divided into 8 chapters, and each of them ends with exercises that support learning. If you know the correct method, solving these problems can be easy, and maths becomes a scoring subject. You can find the solutions for the Maths subject in the link given below:

NCERT Solutions for Class 7 Maths

NCERT Solutions for Class 7 Science

The Science book (Curiosity) comprises 10 chapters dealing with subject matter such as natural resources, motion, gravity, sound, atoms and molecules, tissues, and cells. There are exercises in each chapter containing questions which are described simply and elaborately to make concepts easy for students to grasp. You can find the solutions for the Science subject in the link given below:

NCERT Solutions for Class 7 Science

Benefits of Class 7 NCERT Solutions

Here are five simple benefits of the solutions:

Simple to Learn: The solutions simplify difficult subjects, and it becomes easy for students to understand concepts and learn effectively.
Easy Learning: Students can learn at their own speed and access any topic at any time, even if they miss a few classes.
Preparation for Exams: They identify major topics, include mock tests, and provide different types of questions to help students prepare well for exams.
Improved Problem-Solving Ability: Logical step-by-step explanations provide improvement in analytical ability and solving problems, especially for topics such as math and science.
Improves Self-Confidence: Practising with them improves students' understanding of weaknesses and provides better exam performance

NCERT Books for Class 7 - Other Books Links

Frequently Asked Questions (FAQs)

Q: How many chapters are there in NCERT class 7 Maths

There are 8 chapters in the NCERT class 7 Maths

Q: How many chapters are there in NCERT class 7 Science

There are 12 chapters in the NCERT class 7 Science

Q: How to Get NCERT Solutions PDFs for Class 7?

You can access NCERT Class 7 solutions for science and maths by following the steps given below:

The subject-wise links are given below.
Click on the subject you need to check the NCERT solutions for Class 7.
The chapter-wise links will be given in a table.
Click on the chapter you wish to study the answers for NCERT Class 7th.
The exercise with the detailed NCERT class 7 solutions will be displayed on the screen.
Check how to solve the questions and then practise on your own.
You can even download or print the NCERT solutions for class 7 of the chapter to keep on your desk till you get it right.

Q: How do NCERT Solutions PDFs help students?

They provide detailed, step-by-step explanations for textbook questions, help clarify concepts, assist in homework and exam preparation, and improve problem-solving skills. The solutions are designed in simple language for better understanding.

Q: What subjects are covered in the NCERT Solutions for Class 7 PDFs?

The solutions cover all main subjects like Mathematics and Science prepared according to the latest CBSE syllabus for 2025-26.

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Popular Questions

A block of mass 0.50 kg is moving with a speed of 2.00 ms^-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1) $0.34\; J$	Option 2) $0.16\; J$
Option 3) $1.00\; J$	Option 4) $0.67\; J$

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A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times. Assume that the potential energy lost each time he lowers the mass is dissipated. How much fat will he use up considering the work done only when the weight is lifted up ? Fat supplies 3.8×10⁷J of energy per kg which is converted to mechanical energy with a 20% efficiency rate. Take g = 9.8 ms⁻² :

Option 1)

2.45×10⁻³ kg

Option 2)

6.45×10⁻³ kg

Option 3)

9.89×10⁻³ kg

Option 4)

12.89×10⁻³ kg

Read Complete Answer

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1) $2,000 \; J - 5,000\; J$	Option 2) $200 \, \, J - 500 \, \, J$
Option 3) $2\times 10^{5}J-3\times 10^{5}J$	Option 4) $20,000 \, \, J - 50,000 \, \, J$

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A particle is projected at 60⁰ to the horizontal with a kinetic energy $K$ . The kinetic energy at the highest point

Option 1) $K/2\,$	Option 2) $\; K\;$
Option 3) $zero\;$	Option 4) $K/4$

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In the reaction,

$2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}$

Option 1) $11.2\, L\, H_{2(g)}$ at STP is produced for every mole $HCL_{(aq)}$ consumed	Option 2) $6L\, HCl_{(aq)}$ is consumed for ever $3L\, H_{2(g)}$ produced
Option 3) $33.6 L\, H_{2(g)}$ is produced regardless of temperature and pressure for every mole Al that reacts	Option 4) $67.2\, L\, H_{2(g)}$ at STP is produced for every mole Al that reacts .

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How many moles of magnesium phosphate, $Mg_{3}(PO_{4})_{2}$ will contain 0.25 mole of oxygen atoms?

Option 1) 0.02	Option 2) 3.125 × 10^-2
Option 3) 1.25 × 10^-2	Option 4) 2.5 × 10^-2

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If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1) decrease twice	Option 2) increase two fold
Option 3) remain unchanged	Option 4) be a function of the molecular mass of the substance.

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With increase of temperature, which of these changes?

Option 1) Molality	Option 2) Weight fraction of solute
Option 3) Fraction of solute present in water	Option 4) Mole fraction.

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Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol^-1) is

Option 1) twice that in 60 g carbon	Option 2) 6.023 × 10²²
Option 3) half that in 8 g He	Option 4) 558.5 × 6.023 × 10²³

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A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t²) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m² , the number of rotations made by the pulley before its direction of motion if reversed, is