NCERT Solutions for Class 9 Science Chapter 2 Is Matter Around Us Pure

Shivani PooniaUpdated on 19 Oct 2025, 06:26 PM IST

Did you know the water that looks crystal clear, tastes fine, and feels refreshing contains dissolved impurities in the form of salts, gases, and minerals? Everything we see, touch, or eat is made up of matter, whether it is the air we breathe, the water we drink, the food we eat, or the buildings we see. But the main question is whether the matter around us is pure? The answer to this question lies in is matter around us pure ncert solutions.

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NCERT Solutions for Class 9 Science Chapter 2 Is Matter Around Us Pure Download PDF
NCERT Solutions for Class 9 Science Chapter 2 (In-text Questions)
NCERT Solutions for Class 9 Science Chapter 2 (Exercise Questions)
Practice Questions for Class 9 Science Is Matter Around Us Pure
Approach to Solve Questions of Class 9 Science Chapter 2
Topics Of NCERT Solutions For Class 9 Science Chapter 2
What Students Learn from NCERT Solutions for Class 9 Science Chapter 2
Importance of Class 9 Science Chapter 2 Is Matter Around Us Pure? Solutions
NCERT Solutions for Class 9 Science- Chapter Wise
NCERT Books and NCERT Syllabus

NCERT Solutions for Class 9 Science Chapter 2

These NCERT Solutions for Class 9 Science Chapter 2 Is Matter Around Us Pure help students to understand topics like the difference between pure substances and mixtures, why most of the substances around us are mixtures, and what homogeneous and heterogeneous mixtures. The NCERT Solutions Class 9 Science are designed by our subject experts in a very detailed and comprehensive manner that will help the students to understand the basic concepts. These solutions cover all the questions given in this chapter additionally selected important questions and approaches to solve questions are also added in this article.

NCERT Solutions for Class 9 Science Chapter 2 Is Matter Around Us Pure Download PDF

Get the complete solutions to all textbook questions. Download class 9 science chapter 2 is matter around us pure solutions pdf for exam preparation from the download icon given below. These well structured NCERT Solutions will help you build a strong conceptual understanding.

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NCERT Solutions for Class 9 Science Chapter 2 (In-text Questions)

Given below the detailed is matter around us pure class 9 question answer given in the NCERT textbook. These answers are designed to help students understand the fundamental concepts of this chapter.

Topic 2.1 What is a mixture?, Page 15

Question 1. What is meant by a substance?

Answer:

Substance-
A substance is a matter that consists of a single type of particle and has specific properties. For example, tin, sulfur, pure sugar (sucrose), etc.

Question 2. List the points of differences between homogeneous and heterogeneous mixtures.

Answer:

The differences between homogeneous and heterogeneous mixtures-

HOMOGENEOUS	HETEROGENOUS
1. It has uniform compositions. 2. No visible boundaries of separation. 3. It consists of only one phase. examples- sugar + water = sugar solution	1. It does not have a uniform composition 2. Visible boundaries of separation 3. They consist of more than one phase. examples- sugar +sand = sugar + sand

Topic 2.2 What is a solution?, Page 18

Question 1. Differentiate between homogeneous and heterogeneous mixtures with examples.

Answer:

Homogeneous Mixture: It is a mixture in which different constituents are mixed uniformly and these constituents cannot be easily separated.

Example: Sugar solution, soda, water, soft drinks, vinegar, air, etc.

But,

Heterogeneous mixtures: It is a mixture in which different constituents are not mixed uniformly and the constituents can be easily seen and can be easily separated.

Example: Sugar and sand mixture, milk, ink, paint, wood, blood, etc.

Question 2. How are sol, solution and suspension different from each other?

Answer:

The difference between sol, solution and suspension are given below:

Sol(Colloids)	Suspension	Solution
1. Heterogeneous mixture	1. Heterogeneous mixture	1.Homogeneous mixture
2. We cannot see the size of the particle with the naked eye.	2. Particles are visible to the human naked eye	2. The particles are not visible to the naked eye.
3. They can scatter the beam of light passing through them	3. Scatters the beam of light passing through them	3. unable to scatter the beam of light.
4. Solute particles cannot be separated by filtration and sedimentation.	4. Solute particles can be separated by filtration	4. Solute particles cannot be separated by filtration and sedimentation.

Question 3. To make a saturated solution, 36 g of sodium chloride is dissolved in 100 g of water at 293 K. Find its concentration at this temperature.

Answer:

Given that,

Mass of solute (sodium chloride) = 36 g = $w_1$
Mass of water (as a solvent) = 100 g = $w_2$

Therefore, the total mass of solution = 100 + 36 = 136 g = $W$

According to the question,
Concentration = $\frac{w_1}{W}\times 100$
$=\frac{36}{136}\times 100$
$=26.47$ %

Hence, the concentration of the solution at 293 K is 26.47%

Topic 2.3 Separating the components of a mixture

Question 1. How will you separate a mixture containing kerosene and petrol (difference in their boiling points is more than 25ºC), which are miscible with each other?

Answer:

The mixture of kerosene and petrol which are miscible with each other can be separated by the distillation method.

Take the mixture in a distillation flask and fit it with the thermometer. Heat the mixture slowly. As the boiling point of petrol is lower than that of kerosene, so, petrol vaporizes first. It condenses in the condenser and is collected from the outlet.

And thus kerosene is left in the flask.

Question 2. Name the technique to separate

(i) butter from curd,
(ii) salt from sea-water
(iii) camphor from salt.

Answer:

The following techniques are used to separates them-

(i) Butter from curd can be seperated from Centrifugation method

(ii) Salt from sae water can be seperated from Evaporation

(iii) Camphor from salt can be seperated from Sublimation.

Question 3. What type of mixtures are separated by the technique of crystallization?

Answer:

The crystallization technique is used to purify solids.

Crystallization is used to separate solid- liquid mixtures, specifically to obtain pure solids from their impure or dissolved form in a solution. It is commonly used for substances that decompose on heating or cannot be purified by evaporation.

Topic 2.4 Physical and Chemical changes, Page 19

Question 1 Classify the following as chemical or physical changes:

• Cutting of trees,

• Melting of butter in a pan,

• Rusting of almirah,

• Boiling of water to form steam,

• Passing of electric current, through water and the water breaking down into hydrogen and oxygen gases,

• Dissolving common salt in water,

• Making a fruit salad with raw fruits, and

• Burning of paper and wood

Answer:

Physical changes are:

Cutting of trees
Melting of butter in a pan
Boiling of water to form steam
Dissolving common salt in water
Making a fruit salad with raw fruits

Chemical changes are:

Rusting of almirah,
Passing of electric current, through water and the water breaking down into hydrogen and oxygen gases,
Burning of paper and wood

Question 2. Try segregating the things around you as pure substances or mixtures.

Answer:

Pure substance - Distilled Water, oxygen, iron, sugar, and gold

Mixtures- plastic papers, air, soft drink, salt solution and milk

NCERT Solutions for Class 9 Science Chapter 2 (Exercise Questions)

Given below the class 9 science chapter 2 is matter around us pure solutions for all exercise questions from the textbook. You can also download these solutions of NCERT to get detailed explanation for every question.

Question 1. Which separation techniques will you apply for the separation of the following?

(a) Sodium chloride from its solution in water.
(b) Ammonium chloride from a mixture containing sodium chloride and ammonium chloride.
(c) Small pieces of metal in the engine oil of a car.
(d) Different pigments from an extract of flower petals.

(e) Butter from curd.
(f) Oil from water.
(g) Tea leaves from tea.
(h) Iron pins from sand.
(i) Wheat grains from husk.

(j) Fine mud particles suspended in water.

Answer:

The following separation techniques are used to separate-

a) Sodium chloride from its solution in water by Evaporation method

b) Ammonium chloride from a mixture containing sodium chloride and ammonium chlorid. by Sublimation

c) Small pieces of metal in the engine oil of a car by filtration.

d) Different pigments from an extract of flower petals by chromatography,

e) Butter from curd by centrifugation,

f) Oil from water by separation funnel

g) Tea leaves from tea by filtration,

h) Iron pins from sand by magnetic separation,

i) Wheat grains from husk by winnowing or sedimentation,

j) Fine mud particles suspended in water by decantation and filtration .

Question 2. Write the steps you would use for making tea. Use the words solution, solvent, solute, dissolve, soluble, insoluble, filtrate and residue.

Answer:

The steps for making a tea-

Use water as a solvent and boil it for a few minutes.
Now, add some tea leaves and sugar, and milk (if you want) as a solvent.
Again, boil it for a few minutes so that the sugar will dissolve in it.
At last, filter the solution. Collect the filtrate in a cup. The insoluble tea leaves left behind as a residue.

Question 3. (a) Pragya tested the solubility of three different substances at different temperatures and collected the data as given below (results are given in the following table, as grams of a substance dissolved in 100 grams of water to form a saturated solution).

What mass of potassium nitrate would be needed to produce a saturated solution of potassium nitrate in 50 grams of water at 313 K?

Answer:

We have,
Mass of potassium nitrate = 62g in 100 g of water

Therefore, according to the question,
Mass of potassium nitrate in 50 g of water at 313K
$= \frac{62\times 50}{100} = 31g$

Question 3.(b) Pragya tested the solubility of three different substances at different temperatures and collected the data as given below (results are given in the following table, as grams of a substance dissolved in 100 grams of water to form a saturated solution).

Pragya makes a saturated solution of potassium chloride in water at 353 K and leaves the solution to cool at room temperature. What would she observe as the solution cools? Explain.

Answer:

Pragya will observe that, on cooling the saturated solution, the crystals of potassium chloride will be obtained.

Question 3. (c) Pragya tested the solubility of three different substances at different temperatures and collected the data as given below (results are given in the following table, as grams of a substance dissolved in 100 grams of water to form a saturated solution).

Find the solubility of each salt at 293 K. Which salt has the highest solubility at this temperature?

Answer:

The solubility of each salt at 293K is

Potassium nitrate = 32g
Sodium chloride = 36g
Potassium chloride = 35 g
Ammonium chloride = 37g

Question 3. (d) Pragya tested the solubility of three different substances at different temperatures and collected the data as given below (results are given in the following table, as grams of a substance dissolved in 100 grams of water to form a saturated solution).

What is the effect of a change in temperature on the solubility of a salt?

Answer:

Solubility is directly proportional to the temperature.

Therefore, on increasing temperature, the solubility of salt increases.

Question 4. (a) Explain the following giving examples.

saturated solution

Answer:

Saturated solution - In a given solvent, when no more solute can be dissolved in a solution at a given temperature is called a saturated solution.

Question 4. (b) Explain the following giving examples

pure substance

Answer:

Pure substance -

A pure substance is a matter that consists of a single type of particle and has specific properties. For example, tin, sulphur, pure sugar (sucrose), etc.

Question 4. (c) Explain the following giving examples.

Colloid

Answer:

colloid -
A colloid is a solution in which the solute particle is larger in size compared to the true solution. It is a heterogeneous mixture. Because of the small size of colloidal particles, we cannot see them with our naked eyes. For example, milk and blood.

Question 4. (d) Explain the following giving examples.

(d) suspension

Answer:

Suspension-
It is a heterogeneous solution in which the solute particles do not dissolve in the solvent but remain suspended throughout the bulk of the medium. Particles are visible by the naked eye. Chalkwater is an example of this type of solution.

Question 5. Classify each of the following as a homogeneous or heterogeneous mixture.

soda water, wood, air, soil, vinegar, filtered tea.

Answer :

Homogeneous mixture	Heterogeneous mixture
Soda water	Wood
Vinegar	Soil
Filtered tea
Air

Question 6. How would you confirm that a colourless liquid given to you is pure water?

Answer:

By boiling the give colourless water, we can check whether it is pure or not. If it is pure then the water boils at 100 $^0C$ at atmospheric pressure.

This is because the melting and boiling points of a pure substance don't change.

Question 7. Which of the following materials fall in the category of a “pure substance”?

(a) Ice

(b) Milk

(d) Hydrochloric acid

(e) Calcium oxide

(f) Mercury

(g) Brick

(h) Wood

(i) Air

Answer:

A pure substance is a matter that consists of a single type of particle and has specific properties-
Therefore, the following given substances are '' pure substances" -

Ice
Iron
Hydrochloric acid
calcium oxide and
Mercury

Question 8. Identify the solutions among the following mixtures.

(a) Soil

(b) Seawater

(d) Coal

(e) Soda water

Answer:

A solution is a homogeneous mixture of two or more two substances.

So, according to the definition, out of the given seawater, air, and soda water are examples of solutions.

Question 9. Which of the following will show the “Tyndall effect”?

(a) Salt solution

(b) Milk

(d) Starch solution.

Answer:

Tyndall effect is shown by the colloidal solution and suspension, and it is not shown by a true solution.

Therefore, in the above-given solution, only the milk and starch solution will be able to scatter the light and hence show the Tyndall effect.

Question 10. Classify the following into elements, compounds, and mixtures.

(a) Sodium

(b) Soil

(d) Silver

(e) Calcium carbonate

(f) Tin

(g) Silicon

(h) Coal

(i) Air

(j) Soap

(k) Methane

(l) Carbon dioxide

(m) Blood

Answer:

Elements cannot be broken down into any simpler substance and the compounds have fixed composition can be broken down into elements by chemical or electrochemical reactions. Mixtures have no fixed composition; they are either homogeneous or heterogeneous.

Elements	Compounds	Mixtures
Sodium	Calcium carbonate	Soil
Silver	Carbon dioxide	Sugar solution
Tin	Methane	Coal
Silicon		Air
		Blood
		Soup

Question 11. Which of the following are chemical changes?

(a) Growth of a plant

(b) Rusting of iron

(d) Cooking of food

(e) Digestion of food

(f) Freezing of water

(g) Burning of a candle.

Answer:

Given following are examples of chemical changes-

Growth of plants
Rusting of iron
cooking of food
Digestion of food
Burning of candle

Practice Questions for Class 9 Science Is Matter Around Us Pure

Students can strengthen their understanding of the topic with these is matter around us pure class 9 question answer. These NCERT Solutions for Class 9 provide step by step explanations that make learning easy.

Question 1. Define a pure substance. Give two examples.
Answer:
A pure substance is a single kind of matter that has a uniform composition and the same properties throughout.
Examples: Distilled water and oxygen gas.

Question 2. Name and explain any two methods used for the separation of components of a mixture.
Answer:
Filtration- Used to separate an insoluble solid from a liquid. For example, sand can be separated from water using a filter paper.
Evaporation- Used to separate a dissolved solid from a liquid. For instance, salt can be separated from salt water by heating it until the water evaporates, leaving the salt behind.

Question 3. What is a solution? Mention its three main properties.
Answer:
A solution is a homogeneous mixture of two or more substances.
The three properties are-
It has a uniform composition throughout.
The particles are so small that they cannot be seen with the naked eye.
The solute does not settle down and cannot be separated by filtration.

Question 4. How would you separate a mixture of salt and sand?
Answer:
To separate salt and sand, we can
Add water to the mixture. Salt dissolves, sand does not.
Filter the mixture to separate sand.
Evaporate the filtrate to get salt crystals.

Question 5: Name any three methods used to separate mixtures.

Answer:

Methods that are used to seperate mixture are:

1. Filtration

2. Evaporation

3. Distillation

Approach to Solve Questions of Class 9 Science Chapter 2

It is important to understand concepts before solving class 9 science chapter 2 is matter around us pure question answer. Whether you are learning for the first time or revising for the exams these approaches are very helpful. Given below some points to follow while solving questions of this chapter:

1. Try to understand important terms like mixture, compound, solution, suspension, colloid, solute, solvent, etc. These are frequently asked in both short and long answer questions. Students can also refer to is matter around us pure class 9 notes.

2. While solving questions, it is essential to determine what is given and what we have to find out. Find out the key terms like elements, compounds, colloids, suspension, mixture, etc This helps to understand what is asked in the question.

3. Learn to know the differences between homogeneous and heterogeneous mixtures. You can practice by giving everyday examples for each. Also, focus on methods like filtration, evaporation, distillation, sublimation, and centrifugation for this refer is matter around us pure ncert solutions.

4. Draw neat, labelled diagrams for separation processes and solubility experiments to strengthen your understanding and presentation.

5. Solving questions from NCERT textbooks, as these questions are asked directly in exams. For revision, it is very important to solve questions regularly.

Topics Of NCERT Solutions For Class 9 Science Chapter 2

All the NCERT topics are given below and are thoroughly explained in the is matter around us pure class 9 question answer. This helps students understand each concept clearly and build a strong understanding of the chapter.

2.1 What is a Mixture?

2.1.1 Types of mixture

2.2 What is a Solution?

2.2.1 Concentration of a solution

2.2.2 What is a Suspension?

2.2.3 What is a Colloidal Solution?

2.3 Physical and Chemical Changes

2.4 What are the types of pure substances

2.4.1 Elements

2.4.2 Compounds

What Students Learn from NCERT Solutions for Class 9 Science Chapter 2

These NCERT Solutions for Class 9 Science Chapter 2 Is Matter Around Us Pure help students understand the concepts of pure substances and mixtures in a clear and structured way. Apart from this, students learn many interesting facts and things, which are given below:

These solutions help students to understand the types of substances and the difference between pure substances and mixtures.
What are mixtures, their types, difference between homogeneous and heterogeneous mixtures are well explained in is matter around us pure class 9 question answer.
Here, students understand solutions, suspensions, and colloids and their properties. With this, their separation techniques are also discussed.
Properties of Solutions and the concepts like solute, solvent, concentration, and saturation are well explained in is matter around us pure ncert solutions.

Importance of Class 9 Science Chapter 2 Is Matter Around Us Pure? Solutions

The class 9 science is matter around us pure question answer help students understand the nature of substances and how mixtures and pure substances differ. Given below are some points on why these solutions are important:

1. These solutions help students clearly understand the difference between pure substances and mixtures and their types.

2. Forms the foundation for advanced chemistry topics like compounds, elements, and separation techniques.

3. The class 9 science is matter around us pure question answer shows how separation techniques such as filtration, evaporation, and distillation are used in daily life and industries.

4. They provide detailed solutions that help students in writing precise answers.

5. NCERT Solutions cover all textbook questions that are commonly asked in school and board exams.

NCERT Solutions for Class 9 Science- Chapter Wise

Students can also explore the NCERT Solutions for other Class 8 Science chapters along with the class 9 science chapter 2 is matter around us pure solutions to build a thorough understanding of all topics.

NCERT Solutions for Class 9 Chapter 1 Matter in Our Surroundings

NCERT Solutions for Class 9 Chapter 2 Is Matter Around Us Pure

NCERT Solutions for Class 9 Chapter 3 Atoms and Molecules

NCERT Solutions for Class 9 Chapter 4 Structure of The Atom

NCERT Solutions for Class 9 Chapter 5 The Fundamental Unit of Life

NCERT Solutions for Class 9 Chapter 6 Tissues

NCERT Solutions for Class 9 Chapter 7 Motion

NCERT Solutions for Class 9 Chapter 8 Force and Laws of Motion

NCERT Solutions for Class 9 Chapter 9 Gravitation

NCERT Solutions for Class 9 Chapter 10 Work and Energy

NCERT Solutions for Class 9 Chapter 11 Sound

NCERT Solutions for Class 9 Chapter 12 Improvement in Food Resources

NCERT Books and NCERT Syllabus

Get your hands on the NCERT books and syllabus by following the links below

NCERT Books Class 9 Science

NCERT Syllabus Class 9 Science

NCERT Books Class 9

NCERT Syllabus Class 9

Frequently Asked Questions (FAQs)

Q: What are NCERT Solutions for Class 9 Science Chapter 2 Is Matter Around Us Pure?

Class 9 Science Chapter 2 NCERT Solutions provide detailed answers to all textbook questions based on the concept of pure substances and mixtures. They help students understand types of mixtures, separation techniques, and properties of solutions clearly, making it easier to learn and revise the chapter.

Q: How are pure substances defined in NCERT Solutions for Class 9 Science Chapter 2?

Pure substances are defined as materials that have a uniform and definite composition. They consist of a single type of particle and cannot be separated into other substances by physical methods.

Q: What is a suspension? Is it a homogeneous or heterogeneous mixture?

A suspension is a heterogeneous mixture in which solid particles are dispersed in a liquid but are not dissolved. The particles are large enough to be seen with the naked eye and will settle down over time. Example: Muddy water, chalk powder in water.

Q: Can you explain the significance of separation techniques mentioned in the chapter?

Separation techniques are significant because they allow us to isolate and purify components of mixtures. The chapter introduces various methods such as filtration, evaporation, and magnetic separation.

Q: What is the Tyndall effect, and which type of mixture exhibits it?

The Tyndall effect is the scattering of light by the particles in a colloid or a very fine suspension. This makes the path of a beam of light visible as it passes through the mixture. The Tyndall effect is not observed in true solutions because the particles are too small to scatter light

Q: What are some examples of pure substances?

Some examples of pure substances include elemental substances like iron, gold, and hydrogen, as well as compounds like water, carbon dioxide, and sodium chloride.

Q: What is Chapter 2 of NCERT solutions for Class 9 science?

Chapter 2 of NCERT Science Class 9 is titled as Is Matter Around Us Pure. It focuses on explaining the difference between pure substances and mixtures, types of mixtures, their properties, and various methods used to separate mixtures.

Q: How are NCERT answers structured?

NCERT answers are structured in a clear manner to help students learn easily. They begin with a direct response, followed by explanations, reasoning, and examples or diagrams when needed.

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